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17x^2-2.7x+.09=0
We add all the numbers together, and all the variables
17x^2-2.7x+0.09=0
a = 17; b = -2.7; c = +0.09;
Δ = b2-4ac
Δ = -2.72-4·17·0.09
Δ = 1.17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.7)-\sqrt{1.17}}{2*17}=\frac{2.7-\sqrt{1.17}}{34} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.7)+\sqrt{1.17}}{2*17}=\frac{2.7+\sqrt{1.17}}{34} $
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